# What are the products of this reaction: HC_2H_3O_2 + NaHCO_3 ->?

$C {H}_{3} C O O H \left(a q\right) + H C {O}_{3}^{-} \left(a q\right) r i g h t \le f t h a r p \infty n s C {H}_{3} C O {O}^{-} \left(a q\right) + {H}_{2} C {O}_{3} \left(a q\right)$
But we need to consult $p {K}_{\text{a}}$ values to understand what side the equilibrium favors.
Carbonic acid (${H}_{2} C {O}_{3}$) has a $p {K}_{\text{a}}$ of approximately $6.4$, whereas acetic acid has a $p {K}_{\text{a}}$ of approximately $4.8$.