# What are the removable and non-removable discontinuities, if any, of #f(x)=(2x^2+4x-6) / (x-1)#?

##### 1 Answer

There is a removable discontinuity at

#### Explanation:

So

#=lim_(xrarr1)(2x+6)#

# = 2+6 = 8#

Because the limit exists, the discontinuity is removable.