What are the roots of the equation #4x ^ { 2} = 2+ 7x#?
1 Answer
Mar 26, 2017
#x=2#
#x=-1/4#
Explanation:
Given -
#4x^2=2+7x#
#4x^2-7x-2=0#
#x^2-7/4x-2/4=0#
#x^2-7/4x-1/2=0#
#x^2-7/4x=1/2#
#x^2-7/4x+49/64=1/2+49/64= (32+49)/64=81/64#
#(x^2-7/8)^2=81/64#
#(x-7/8)=+-sqrt(81/64)#
#(x-7/8)=+-9/8#
#x=9/8+7/8=(9+7)/8=16/8=2#
#x=2#
#x=-9/8+7/8=(-9+7)/8=-2/8=-1/4#
#x=-1/4#
