# What are the solution(s) to the following system of equations #y = -x^2# and y = x?

##### 1 Answer

Aug 8, 2016

x = 0 , x = - 1

#### Explanation:

Since we are given 2 values that y equates to we can equate the right sides.

#rArrx=-x^2rArrx^2+x=0# factorising :

#x(x+1)=0#

#rArrx=0" or " x+1=0rArrx=-1# The solutions are

#x=0,x=-1#