# What are the solution(s) to the following system of equations y = -x^2 and y = x?

Aug 8, 2016

x = 0 , x = - 1

#### Explanation:

Since we are given 2 values that y equates to we can equate the right sides.

$\Rightarrow x = - {x}^{2} \Rightarrow {x}^{2} + x = 0$

factorising : $x \left(x + 1\right) = 0$

$\Rightarrow x = 0 \text{ or } x + 1 = 0 \Rightarrow x = - 1$

The solutions are $x = 0 , x = - 1$