What are the solutions boundaries to abs(x-10)<1?

1 Answer
Oct 27, 2016

$| x - 10 |$ is always non-negative.

Explanation:

So the lowest value is $0$
The highest value is $1$, as given, so:
$0 \le | x - 10 | < 1$

These belong to $x$-values of
$10 \le x < 11$ and $9 < x \le 10$
Since these are adjacent the answer is $9 < x < 11$
graph{|x-10| [-0.44, 15.36, -1.35, 6.55]}