What are the solutions of #x^2-8-5x#?

1 Answer
Sanjay VN
Jan 21, 2018

#x^2 - 5x -8#
for any quadratic equation #ax^2 + bx +c# the roots are given by
#x = (-b +- root()(b^2 - 4ac))/(2a)#
so using the above formula
#x = (5 +- root()(25 - 4*1*(-8)))/(2)#
which is
#x = (5+- root()(25 + 32))/2#
the roots are
#x = (5 + root()(57))/2 and (5 - root()(57))/2 #
hope you find it helpful :)

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