What are the values and types of the critical points, if any, of f(x)=e^(-2x^2)-xe^x?

1 Answer
Jun 16, 2018

P_max(-0.182115825969939296277,1.087614208523047937841)

Explanation:

We get
f'(x)=-e^(-2x^2)(e^(x+2x^2)+4x+e^(x+2x^2)x)
By a numerical method we get
x_1approx -0.182115825969939296277
and
f''(x)=-e^(-2x^2)(4+2e^(x+2x^2)+e^(x+2x^2)x-16x^2)
and

f''(x_1)<0
so we get a maximum.