# What are the vertical asymptotes of #f(x) = (2)/(x^2 - 1)#?

##### 1 Answer

Aug 24, 2014

*Vertical asymptotes for this function will occur when the denominator is negative. Therefore, it behooves us to find the zeroes of the function in the denominator, namely #x^2 -1#. Factoring, we get #x^2-1 = (x-1)(x+1)# and thus our zeroes occur at #x=+-1#. Ergo, the locations of our vertical asymptotes are also #x=+-1#.*

For a more thorough explanation of the concept of vertical asymptotes, go here: http://socratic.org/questions/what-is-a-vertical-asymptote-in-calculus?