What are the x-intercepts of the equation #f(x)=3x^2+10x-8# ?

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Answer 1 · 2017-10-26T05:49:36

#x = 2/3 and x =-4# are the #x#-intercepts

The #x#intercepts are the points where the parabola crosses the #x#-axis.

All along the #x#-axis, #y=0#. This gives us the equation:

#3x^2+10x-8=0" "larr# factorise and solve for #x#

#(3x-2)(x+4)=0#

Set each factor equal to #0#

#3x-2=0" "rarr 3x=2" "rarr x= 2/3#

#x+4=0" "rarr x= -4#