Question

What are the `x`-intercepts of the graph of `y=6x^2+10x-4`?

Answer 1

I found:
`(-2,0)`
and
`(1/3,0)`

Explanation:

You set `y=0` and solve the corresponding equation:

`6x^2+10x-4=0`

using the Quadratic Formula:
`x_(1,2)=(-10+-sqrt(100+96))/12=(-10+-14)/12=`
Two solutions:
`x_1=-24/12=-2`
`x_2=4/12=1/3`

The `x-`intercepts will be:

`(-2,0)`
and
`(1/3,0)`

Graphically:
graph{6x^2+10x-4 [-10, 10, -5, 5]}