What are the zeroes in the function #f(x) = 3x^2-26x+16#?

1 Answer
sankarankalyanam
Oct 17, 2017

#x=2/3, 8#
graph{3x^2-26x+16 [-10, 10, -5, 5]}

Explanation:

Roots are also called x-intercepts or zeroes. A quadratic equation is graphically represented by a parabola with vertex located at the origin, below the x axis or above. Therefore, to find the roots of the quadratic function, we set f(x) = 0 and solve the equation #ax^2 + bx + c = 0#

#3x^2-26x+16 = 0#
#3x^2-24x-2x+16=0#
#3x(x-8) -2(x-8) = 0#
#(3x-2)*(x-8) = 0#
#:.(3x-2) = 0 or x = 2/3, x - 8 = 0 or x = 8#

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