# What are the zeros of f(x)= −4x^5 + 3?

The answer is: $x = {24}^{\frac{1}{5}} / 2$.
It is sufficient to solve the system between the function and the line $y = 0$ (x-axis).
-4x^5+3=0rArrx^5=3/4rArrx=""(3/4)^(1/5)=3^(1/5)/2^(2/5)=
$= {3}^{\frac{1}{5}} / {2}^{\frac{2}{5}} \cdot {2}^{\frac{3}{5}} / {2}^{\frac{3}{5}} = {\left(3 \cdot {2}^{3}\right)}^{\frac{1}{5}} / 2 = {24}^{\frac{1}{5}} / 2$.