What are the zeros of #f(x) = x^2 - 2x - 35#?

2 Answers
marfre
May 4, 2018

#x = -5, x = 7#

Explanation:

Given: #f(x) = x^2 - 2x - 35#

Zeros are the #x#-values when #y = 0#. They are also called #x#-intercepts when presented as an ordered pair #(x, 0)#.

To find zeros, set #f(x) = 0# and factor or use the quadratic formula.

#f(x) = x^2 - 2x - 35 = (x +5)(x - 7) = 0#

#(x + 5)# and #(x-7)# are called linear factors.

Set each linear factor equal to zero to find the zeros:

#x + 5 = 0; " " x - 7 = 0#

#x = -5, x = 7#

Jim G.
May 4, 2018

#x=-5" and "x=7#

Explanation:

#"set "f(x)=0#

#rArrx^2-2x-35=0#

#"the factors of - 35 which sum to - 2 are - 7 and + 5"#

#rArr(x-7)(x+5)=0#

#"equate each factor to zero and solve for x"#

#x+5=0rArrx=-5#

#x-7=0rArrx=7#

#rArrx=-5,x=7larrcolor(red)" are the zeros"#

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