What are three consecutive even integers such that the sum of the first and twice the second is 20 more than the third?

1 Answer
Apr 23, 2016

10, 12, 14

Explanation:

Let xx be the smallest of the 3 integers
=> the second integer is x + 2x+2
=> the largest integer is x + 4x+4


x + 2(x + 2) = x + 4 + 20x+2(x+2)=x+4+20
=> x + 2x + 4 = x + 24x+2x+4=x+24
=> 3x + 4 = x + 243x+4=x+24
=> 2x = 20 2x=20=> x = 10#


=> x + 2 = 12x+2=12
=> x + 4 = 14x+4=14