# What does pOH stand for?

May 9, 2016

This the base analogue of $p H$. $p O H$ $=$ $- {\log}_{10} \left[H {O}^{-}\right]$
In water, by definition, $p H + p O H = 14$.
And likewise for an aqueous acid, $p {K}_{a} + p {K}_{b} = 14$.
So what is $p O H$ of a solution that is $0.10 \cdot m o l \cdot {L}^{-} 1$ with respect to $C a {\left(O H\right)}_{2}$?