Question

What does pOH stand for?

Answer 1

This the base analogue of `pH`. `pOH` `=` `-log_(10)[HO^-]`

Explanation:

In water, by definition, `pH + pOH =14`.

And likewise for an aqueous acid, `pK_a + pK_b =14`.

So what is `pOH` of a solution that is `0.10*mol*L^-1` with respect to `Ca(OH)_2`?