# What equivalence factor set should you use to convert from 4.23 x 10^12 atoms of calcium (Ca) to grams of Ca?

Sep 4, 2016

${N}_{A}$ $\text{, Avogadro's number}$. ${N}_{A} = 6.022 \times {10}^{23}$.

#### Explanation:

By definition, ${N}_{A} ,$ $6.022 \times {10}^{23} \text{ calcium atoms}$ have a mass of $40.08 \cdot g$.

And thus,

$\left(4.23 \times {10}^{12} {\text{ calcium atoms")/(6.022xx10^23" calcium atoms mol}}^{-} 1\right) \times 40.08 \cdot g \cdot m o {l}^{-} 1$

$=$ ??g