What id the mass in grams of 2.00 x 10^23 molecules of F2?

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What id the mass in grams of 2.00 x 10^23 molecules of F2?

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Answer 1 · 2018-02-01T23:10:38

$12.62g F_{2}$ $"12.62g " F_2$

Explanation:

You have to go from molecules, to moles, to grams
Remember $1 mole = 6.02 \cdot 10^{23} molecules$ $"1 mole"= 6.02*10^23 " molecules"$
And then to go to grams you multiply moles by the atomic mass from the periodic table for the element, but since it's F2 you'll have to multiply that mass by 2. So:
Atomic mass of $F_{2} = 38 g$ $F_2= 38g$ . Use dimensional analysis using this conversion factors

$2 \cdot 10^{23} molecules \cdot \frac{1 mol F2}{6.02 \cdot 10^{23} molecules} \cdot \frac{38 g}{1 mole F2} = 12.62g F_{2}$ $2*10^23 " molecules" * ("1 mol F2")/(6.02*10^23 "molecules") *(38g)/"1 mole F2" = "12.62g " F_2$

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What id the mass in grams of 2.00 x 10^23 molecules of F2?

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