What is #(1 3/4+2 3/8) + 5 7/8#?

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Answer 1 · 2018-03-24T07:11:26

#10#

First convert them all into improper fractions

#(1 3/4 + 2 3/8) + 5 7/8#

#(7/4 + 19/8) + 47/8#

Write #7/4# as #14/8#

Now, since they all have the same denominator, we can add the numerators

#=(14+19+47)/8#

#=80/8#

#=10#