Question

What is `(1 + i)^8` in rectangular form?

Answer 1

`(1+i)^8 = 16`

Explanation:

`(1+i)^2 = 1+2i+i^2 = 2i`

`(2i)^2 = 4i^2 = -4`

`(-4)^2=16`

So: `(1+i)^8 = (2i)^4 = (-4)^2 = 16`