What is √18+√12÷√8-√48 in form of A+B√6?

1 Answer

#-9/10-2/5sqrt6#

Explanation:

#"using the "color(blue)"rules of radicals"#

#•color(white)(x)sqrt(ab)hArrsqrtaxxsqrtb#

#•color(white)(x)(sqrta+sqrtb)(sqrta-sqrtb)=a-b#

#"let's begin by simplifying the given radicals"#

#sqrt18=sqrt(9xx2)=sqrt9xxsqrt2=3sqrt2#

#sqrt12=sqrt(4xx3)=sqrt4xxsqrt3=2sqrt3#

#sqrt8=sqrt(4xx2)=sqrt4xxsqrt2=2sqrt2#

#sqrt48=sqrt(16xx3)=sqrt16xxsqrt3=4sqrt3#

#rArr(sqrt18+sqrt12)/(sqrt8-sqrt48)=(3sqrt2+2sqrt3)/(2sqrt2-4sqrt3)#

#"we now require to "color(blue)"rationalise the denominator"#

#"that is, eliminate the radicals from the denominator"#

#"multiply numerator/denominator by the "color(blue)"conjugate"#
#"of the denominator"#

#"the conjugate of "2sqrt2-4sqrt3 " is "2sqrt2color(red)(+)4sqrt3#

#=((3sqrt2+2sqrt3)(2sqrt2+4sqrt3))/((2sqrt2-4sqrt3)(2sqrt2+4sqrt3))#

#"expand the factors using FOIL gives"#

#=(12+12sqrt6+4sqrt6+24)/(8-48)#

#=(36+16sqrt6)/(-40)#

#=36/(-40)+(16sqrt6)/(-40)=-9/10-2/5sqrt6#