# What is 29 degrees celsius in fahrenheit?

Mar 31, 2016

$\textcolor{b l u e}{\text{Fahrenheit temperature } = \left(29 \times \frac{9}{5}\right) + 32 = {84.2}^{o} F}$

#### Explanation:

The numbers to remember are 5, 9 and 32

Fahrenheit are the lager number when comparing like temperature for like. So to convert Centigrade to Fahrenheit, you need to make the numbers bigger. Thus you multiply by $\frac{9}{5}$. To go from Fahrenheit to centigrade you are making the numbers smaller so you multiply by $\frac{5}{9}$

All you need to remember now is that freezing point for each is different.

Centigrade freezing point is ${0}^{o}$
Fahrenheit freezing point is ${32}^{o}$

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$\textcolor{b l u e}{\text{Using this information to answer your question}}$

We are going from Centigrade to Fahrenheit so it is small number to large. So we have $\textcolor{b l u e}{\times \frac{9}{5}}$

We are changing freezing point from 0 on 1 scale to 32 on a different scale so we now have:

$\textcolor{b l u e}{\times \frac{9}{5} + 32}$

Thus the full conversion is:

$\textcolor{b l u e}{\text{Fahrenheit temperature } = \left(29 \times \frac{9}{5}\right) + 32 = {84.2}^{o} F}$

Jun 12, 2017

$\text{84.2"^@"F}$

#### Explanation:

An useful formula:

$\frac{\text{^@"F"-32)/9 = (""^@"C}}{5}$

So that...

$\frac{\text{^@"F} - 32}{9} = \frac{29}{5}$

$5 \times \text{^@"F"= 421}$

$\text{^@"F"= 84.2}$