What is# (-2x^2y^4)^3#?

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Answer 1 · 2018-05-18T05:26:07

#-8x^6y^12#

#(-2)^3=-8#

#(x^2)^3=x^(2 xx3)=x^6#

#(y^4)^3=y^12#

Answer 2 · 2018-05-18T05:29:05

#-8x^6y^12#

#(abc)^3 = a^3b^3c^3# ,
so #(-2x^2y^4)^3=(-2)^3(x^2)^3(y^4)^3# ,

and because #(a^b)^c=a^(bc)#,

#(-2)^3(x^2)^3(y^4)^3=-8x^6y^12# .