What is (-3x^3+11x^2-7)-:(3x^2-2x-1)?

the answer is $\frac{- 3 {x}^{3} + 11 {x}^{2} - 7}{\left(3 x + 1\right) \left(x - 1\right)}$
the first equation can't factor anymore so leave that alone and move on to solve the next equation. $3 \cdot - 1$ gives you $- 3$ and you have to find what multiplies to gives you that and adds up to the middle number: $- 2$. once you get that, it should look like this: $3 {x}^{2} - 3 x - x - 1$ then group then and factor
$\left(3 {x}^{2} - 3 x\right) + \left(x - 1\right)$ then after you factor, you get $\left(3 x + 1\right) \left(x - 1\right)$ then put the other equation in