What is #(-3x^3+11x^2-7)-:(3x^2-2x-1)#?

1 Answer
Chanelle K.
Jan 18, 2018

the answer is #(-3x^3+11x^2-7)/((3x+1)(x-1))#

Explanation:

the first equation can't factor anymore so leave that alone and move on to solve the next equation. #3*-1# gives you #-3# and you have to find what multiplies to gives you that and adds up to the middle number: #-2#. once you get that, it should look like this: #3x^2-3x-x-1# then group then and factor
#(3x^2-3x)+(x-1)# then after you factor, you get #(3x+1)(x-1)# then put the other equation in

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