What is,#-4x+4y+5z=9#,#-2x+2y+z=3#,#-4x+5y=4#?

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Answer 1 · 2018-03-01T01:14:53

#x=-1#, #y=0# and #z=1#

#-4x+4y+5z-5*(-2x+2y+z)=9-5*3#

#6x-6y=-6#, so #6x=6y-6# or #x=y-1#

Hence,

#-4*(y-1)+5y=4#

#y+4=4#, consequently #y=0# and #x=-1#

Thus,

#(-4)*(-1)+4*0+5z=9#

#5z+4=9#, consequently #5z=5# and #z=1#