What is #4^(5n)# greater than 30?

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Answer 1 · 2018-05-02T13:59:23

#n>(log30)/(5log4)#

#n > 0.491#

Assuming: #4^(5n)>30#.

Take logarithms on both sides.

#log(4^(5n))>log30#

#5nlog4>log30#

#5n>(log30)/(log4)#

#n>(log30)/(5log4)#

#n > 0.491#