What is #5(x-2y)^2#, if #x=-3# and #y=-4#?

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Answer 1 · 2016-08-17T18:10:59

#=125#

By plugging #x=-3# and #y=-4# in the equation #5(x-2y)^2#

We get

#5(-3-2times(-4))^2#

#=5(-3+8)^2#

#=5times(5)^2#

#=5times25#

#=125#

Answer 2 · 2016-08-17T18:15:07

#125#

Substitute the given values into the expression.
Then follow the correct order of operations.

#5(color(red)(x) -2color(blue)(y))^2 " "color(red)(x = -3)" "color(blue)(y=-4)#

=#5[color(red)((-3)) - 2color(blue)((-4))]^2#

=#5(-3+8)^2#

=#5(5)^2#

=#5 xx 25#

=#125#