# What is 6 ?divided by the square root of three in simplest radical form

$\frac{6}{\sqrt{3}} \cdot \left(\frac{\sqrt{3}}{\sqrt{3}}\right) =$ rationalizing:
$= \frac{6 \sqrt{3}}{3} = 2 \sqrt{3} = \sqrt{{2}^{2} \cdot 3} = \sqrt{12}$