What is #(-7/(m^2+3)) - 3/(m^2+3)#?

1 Answer
Apr 23, 2017

Since the denominators are both the same we may add/subtract the numerators:

Explanation:

First a rewrite:

#=(-7)/(m^2+3)+(-3)/(m^2+3)#

#=(-7+(-3))/(m^2+3)=(-7-3)/(m^2+3)=(-10)/(m^2+3)#

#=-10/(m^2+3)#

This looks all a bit roundabout, but it may make the steps clearer.