Question

What is `(""_7P_6)/(""_7P_4)`?

Answer 1

`6.`

Explanation:

We have, the Formula : `""_nP_r=(n!)/((n-r)!`

Hence, `(""_7P_6)/(""_7P_4)={(7!)/((7-6)!)}/{(7!)/((7-4)!)}=(3!)/(1!)=3*2*1=6`