What is #8^sqrt6# rounded to three decimal places?

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Answer 1 · 2016-12-13T18:35:09

#8^sqrt(6) ~~ 162.971#

I can't think of a nice way of calculating this by hand, so let's resort to a calculator.

Assuming your calculator has #sqrt(x)# key, #ln x# key and #e^x# key, we can calculate:

#8^sqrt(6) = e^(sqrt(6) * ln(8)) ~~ 162.97074840462838867617#

Truncated to #3# decimal places this would be:

#162.970#

Note however, that the following digit is #7 >= 5#, so we should round up the last digit from #0# to #1# to get:

#8^sqrt(6) ~~ 162.971#