Question

What is `(8x+3y^2)/(4y-3x)` when `x=2` and `y=3`?

Answer 1

`(8x+3y^2)/(4y-3x) = 43/6 = 7 1/6to` when `x=2; y=3`

Explanation:

Given: `(8x+3y^2)/(4y-3x)` and `x=2; y=3`

Substitute the values of `x and y` into the expression:

`(8x+3y^2)/(4y-3x)to` `(8(2)+3(3)^2)/(4(3)-3(2))to` `(16+3(9))/(12-6)to` `(16+27)/(6)to` `(43)/(6)`

`43/6 = ((7xx6)+1)/6 = 7+1/6 = 7 1/6`