What is a particular solution to the differential equation #dy/dx=(4sqrtylnx)/x# with #y(e)=1#?

1 Answer
Feb 11, 2017

# y = ln^4x #

Explanation:

We have:

# dy/dx = (4sqrt(y)lnx)/x #

Which is a first order linear separable Differential Equation, so we can rearrange to get:

# 1/sqrt(y) dy/dx = (4lnx)/x #

and separate the variables to get:

# int \ y^(-1/2) \ dy = int \ (4lnx)/x \ dx #

And then we can integrate to get:

# y^(1/2)/(1/2) = (4)(ln^2x/2) + C #
# :. 2sqrt(y) = 2ln^2x + C #

Using #y(e)=1# we get:

# :. 2 = 2ln^2e + C #
# :. C=0 #

Hence the particular solution is:

# \ \ \ 2sqrt(y) = 2ln^2x #
# :. sqrt(y) = ln^2x #
# :. \ \ \ y = ln^4x #

Validation:
1. # x=e => y = ln^4e = 1 \ # QED
2. #dy/dx = (4ln^3x)/x = (4lnx)/x * ln^2x = (4sqrt(y)lnx)/x \ # QED