What is a solution to the differential equation #dy/dx=x^2y#?
1 Answer
Aug 2, 2016
Explanation:
First, separate the variables:
#dy/dx=x^2y" "=>" "dy/y=x^2dx#
Integrate both sides:
#intdy/y=intx^2dx" "=>" "ln(y)=x^3/3+C#
Solve for
#y=e^(x^3/3+C)=e^(x^3/3)(e^C)=Ce^(x^3/3)#