What is a solution to the differential equation #(y+1)dy/dx=2x#?

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Answer 1 · 2016-08-01T22:51:12

# y =pm sqrt(2 x^2 + C) - 1#

#(y+1)dy/dx=2x#

this has already been separated!

integrating wrt x
#int \ (y+1)dy/dx \ dx=int \ 2x \ dx#

#int \ (y+1) \ dy=2 int \ x \ dx#

# 1/2(y+1)^2 =x^2 + C#

# (y+1)^2 =2 x^2 + C#

# y+1 =pm sqrt(2 x^2 + C)#

# y =pm sqrt(2 x^2 + C) - 1#