Question

What is an equation for a tangent to the graph of `y = Arctan(x/3`) at the origin?

Answer 1

`y= x/3`

Explanation:

First find the slope of the tangent at the origin, which would be given by the value of the derivative of the given function at the origin. `dy/dx= 1/(3 (1+x^2 /9))`. Slope at origin would be `1/3`. Equation of tangent would be y=`x/3`