# What is/are the maximum number of possible real roots of the equation? a) 3 b) 4 c) 5 d) 0

## ${x}^{5} - 6 {x}^{2} - 4 x + 5 = 0$

Apr 5, 2018

See below.

#### Explanation:

None of the answers is satisfactory

Comparing the plots for

$y = {x}^{5}$ and
$y = - 6 {x}^{2} - 4 x + 5$

the conclusion is that there is only a real root.