Question

What is `cos^4thetasin^2theta` in terms of non-exponential trigonometric functions?

Answer 1

`cos^4thetasin^2theta`

`=1/2xx2cos^2thetaxx1/4 (2costhetasintheta)^2`

`=1/2(1+cos2theta)xx1/8 (2sin^2 2theta)`

`=1/16(1+cos2theta) (1- cos4theta)`