What is #csc theta# given that #cot theta = - sqrt15# and #theta# is in quadrant II?

1 Answer
Ratnaker Mehta
Jul 2, 2016

#csctheta=+4#.

Explanation:

We use the Identity : #csc^2theta=1+cot^2theta#

Hence, #csc^2theta=1+15=16 rArr csctheta=+-4#

To determine the sign, we recall that #theta in Q_(II)#, in which #sin# and accordingly, #csc# is #+ve#. Therefore, #csctheta=+4#.

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