Question

What is `f(g(2))` when `f(x) =x-1` and `g(x) = -5x^2 + 14x+7`?

Answer 1

14

Explanation:

First calculate g(2) then f(g(2))

`rArrg(2)=-5(2)^2+14(2)+7=-20+28+7=15`

`rArrf(g(2))=f(15)=15-1=14`