# What is h(f(-2)) given f(x)=x^2 and h(x)=x+4?

Dec 28, 2016

$h \left(f \left(- 2\right)\right) = 8$

#### Explanation:

To solve $\textcolor{b l u e}{h \left(\textcolor{red}{f \left(- 2\right)}\right)}$ we can first solve the function $\textcolor{red}{f \left(- 2\right)}$

$\textcolor{red}{f \left(- 2\right)} = {\left(- 2\right)}^{2} = 4$

$\textcolor{b l u e}{h \left(\textcolor{red}{f \left(- 2\right)}\right)}$ now becomes $\textcolor{b l u e}{h \left(\textcolor{red}{4}\right)}$

$\textcolor{b l u e}{h \left(\textcolor{red}{4}\right)} = 4 + 4 = 8$