Question

What is `int e^(2x)dx`?

Answer 1

The answer is `int e^(2x) dx = (e^(2x))/2 +c`

Explanation:

Note that `int e^(mx) dx = (e^(mx))/m +c`

In your case `m = 2`

So `int e^(2x) dx = (e^(2x))/2 +c`