Question

What is `lim_(->-oo) f(x) = (xe^x)/x^2`?

Answer 1

I think there is some bit missing here!

Explanation:

I supposed (but I may be wrong) you wanted:
`lim_(x->-oo)((xe^x)/x^2)=`
we can write:
`(lim_(x->-oo)(xe^x))/(lim_(x->-oo)(x^2))=(-oo*0)/(oo)=0/oo=0`