Question

What is `lim t->2` of `((t^2-2)/(t^3-3t+5))^2`?

Answer 1

`4/49`

Explanation:

To solve this we just have to plug in 2 for t:

`((t^2-2)/(t^3-3t+5))^2=> ((2^2-2)/(2^3-3(2)+5))^2=(2/7)^2=4/49`

So:

`lim_(t->2)((t^2-2)/(t^3-3t+5))^2=4/49`