Question

What is `\lim_{x \rightarrow 0} \frac{\ln ( 1+ x )}{x}`?

Answer 1

`1`

Explanation:

`log(1+x)/x=log(1+x)^(1/x)` so

`lim_(x->0)log(1+x)/x=lim_(x->0)log(1+x)^(1/x)=log(lim_(x->0)(1+x)^(1/x))=log(e)=1`