What is #lim_(xrarroo) sin(x)/x #?

Question

1795 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-11-09T20:00:13

#lim_(xrarroo)sin(x)/x =0#

By the squeeze theorem

#AAx in RR :-1 <= sin(x) <= 1#

So #-1/x <= sin(x)/x<=1/x#

#lim_(xrarroo) -1/x = 0#

and

#lim_(xrarroo) 1/x = 0#

With the squeeze theorem we can say that

#sin(x)/x = 0#