What is #log_(1/2) 4#?

1 Answer
Sep 29, 2016

Answer:

#-2#

Explanation:

You can rewrite this question easily as

#(1/2)^x=4#

That is the purpose of a log: to find the value of the exponent. For this problem, we simply rewrite it and the do some math. Since

#1/2 < 1" "# and #" "4 > 1#

we know the exponent must be negative. That allows us to write the equation as

#2^(-x) = 4#

So, #2# to the power of what gets us #4#? The answer is #2#

#2^2=4#

Thus, you get #-2#.