Question

What is `log_6 496.8 - log_6 2.3`?

Answer 1

I found that it is equal to `3`

Explanation:

We can write it as:
`log_6(496.8/2.3)=log_6(216)=3`

We use the property of logs:
`loga-logb=log(a/b)`
and the definition of log:
`log_ax=b ->a^b=x`
in:
`log_6(216)=3`

because: `6^3=216`