Question

What is mass of 2,4,6 trinitroaniline C6H2(NO2)3NH2 (Mr 228), that can be obtained from 10g of aniline, C6H5NH2 ( Mr 93)?

a) 24.5g b) 25.5g c) 25g d) 24g

Answer 1

The mass of 2,4,6-trinitroaniline is a) 24.5 g.

Explanation:

The partially balanced equation for the reaction is

`M_text(r):color(white)(mll)93color(white)(mmmmmmmmmll)228`
`color(white)(mm)"C"_6"H"_5"NH"_2 + … → "C"_6"H"_2("NO"_2)_3"NH"_2 + …"`

Step 1. Calculate the moles of aniline

`"Moles of aniline" = 10 color(red)(cancel(color(black)("g aniline"))) × "1 mol aniline"/(93 color(red)(cancel(color(black)("g aniline")))) = "0.108 mol aniline"`

Step 2. Calculate the moles of trinitroaniline

`"Moles of trinitroaniline" = 0.108 color(red)(cancel(color(black)("mol aniline"))) × "1 mol trinitroaniline"/(1 color(red)(cancel(color(black)("mol aniline")))) = "0.108 mol trinitroaniline"`

Step 3. Calculate the mass of trinitroaniline

`"Mass of trinitroaniline" = 0.108 color(red)(cancel(color(black)("mol trinitroaniline"))) × "228 g trinitroaniline"/(1 color(red)(cancel(color(black)("mol trinitroaniline")))) = "24.5 g trinitroaniline"`