What is molecular formula of compound that weighs 46 g/mol and analyzes to 52.2% C, 34.8% O, and 13% H?
As with all these problems, we assume that there are
First we calculate an empirical formula...........
Note (i) that here we have simply divided the atomic masses thru by the
And now we normalize the formula by dividing thru by the lowest molar ratio, that of oxygen to get the empirical formula:
And thus our empirical formula is
But the molecular formula is always a mulitple of the empirical formula:
We KNOW the molecular mass because it has been measured in a separate experiment, and provided for us:
and we solve for