What is ph for the buffer solution prepared from equal volumes of #2.00molL^-1# #H_3C-CO_2H# and #2.00molL^-1# #Na^(+)"^(-)O_2C-CH_3# #(K_a=1.8xx10^-5)#?

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Answer 1 · 2018-04-11T09:54:38

#pH=4.74#

The buffer equation holds that for a buffer solution, i.e. a mixture of weak acid and its conjugate base in appreciable concentrations that...

#pH=pK_a+log_10{[[A^-]]/[[HA]]}#

And so here....

#pH=4.74+log_10{[[AcO^-]]/[[HOAc]]}=4.74+underbrace(log_10{[[2.00*mol*L^-1]]/[[2.00*mol*L^-1]]})_"the which is EQUAL to ZERO"# ..

And since #log_10(1)=0#, #pH=-log_(10)(1.80xx10^-5)=-(-4.74)=4.74#...

What is ph for the buffer solution prepared from equal volumes of #2.00*mol*L^-1# #H_3C-CO_2H# and #2.00*mol*L^-1# #Na^(+)"^(-)O_2C-CH_3# #(K_a=1.8xx10^-5)#?